(2x+5)(x^2+3x-4)=0

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Solution for (2x+5)(x^2+3x-4)=0 equation:


Simplifying
(2x + 5)(x2 + 3x + -4) = 0

Reorder the terms:
(5 + 2x)(x2 + 3x + -4) = 0

Reorder the terms:
(5 + 2x)(-4 + 3x + x2) = 0

Multiply (5 + 2x) * (-4 + 3x + x2)
(5(-4 + 3x + x2) + 2x * (-4 + 3x + x2)) = 0
((-4 * 5 + 3x * 5 + x2 * 5) + 2x * (-4 + 3x + x2)) = 0
((-20 + 15x + 5x2) + 2x * (-4 + 3x + x2)) = 0
(-20 + 15x + 5x2 + (-4 * 2x + 3x * 2x + x2 * 2x)) = 0
(-20 + 15x + 5x2 + (-8x + 6x2 + 2x3)) = 0

Reorder the terms:
(-20 + 15x + -8x + 5x2 + 6x2 + 2x3) = 0

Combine like terms: 15x + -8x = 7x
(-20 + 7x + 5x2 + 6x2 + 2x3) = 0

Combine like terms: 5x2 + 6x2 = 11x2
(-20 + 7x + 11x2 + 2x3) = 0

Solving
-20 + 7x + 11x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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